If the median of the following data is 33 then, find the value of m:

Class	\(\displaystyle f\)	c.f.
$\displaystyle 0$-$\displaystyle 15$	$\displaystyle 17$	$\displaystyle 17$
$\displaystyle 15$-$\displaystyle 30$	$\displaystyle 35$	$\displaystyle 52$
$\displaystyle 30$-$\displaystyle 45$	$\displaystyle 40$	$\displaystyle 92$
$\displaystyle 45$-$\displaystyle 60$	$\displaystyle 18$	$\displaystyle 110$
$\displaystyle 60$-$\displaystyle 75$	\(\displaystyle m\)	\(\displaystyle 110+m\)
$\displaystyle 75$-$\displaystyle 90$	$\displaystyle 2$	\(\displaystyle 112+m\)

Median class is $\displaystyle 30$-$\displaystyle 45$ \[\begin{aligned} & 33=30+\frac{15}{40}\left(\frac{112+m}{2}-52\right) \\ & \Rightarrow m=8 \end{aligned} \]