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Mathematics · 2024 · 1 mark
CBSE 2024 · Region 4 · Set 3 · Q17
If y =1 is one of the solutions of the quadratic equation py^2+ py +3=0, then the value of p is:
If $\displaystyle \mathrm{y}=1$ is one of the solutions of the quadratic equation $\displaystyle \mathrm{py}^{2}+\mathrm{py}+3=0$, then the value of p is :
Official answer
(C)
$\displaystyle -\frac{3}{2}$
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