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Mathematics · 2025 · 1 mark

CBSE 2025 · Region 4 · Set 1 · Q1

If x=a b^3 and y=a^3 b, where a and b are prime numbers, then [ HCF (x, y)- LCM (x, y)] is equal to:

If $\displaystyle x=a b^{3}$ and $\displaystyle y=a^{3} b$, where $\displaystyle a$ and $\displaystyle b$ are prime numbers, then $\displaystyle [\operatorname{HCF}(x, y)-\operatorname{LCM}(x, y)]$ is equal to :
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