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Mathematics · 2024 · 1 mark
CBSE 2024 · Region 3 · Set 1 · Q13
Given HCF (2520,6600)=40, LCM (2520,6600)=252 × k, then the value of k is:
Given $\displaystyle \operatorname{HCF}(2520,6600)=40, \operatorname{LCM}(2520,6600)=252 \times \mathrm{k}$, then the value of k is :
Official answer
(A)
$\displaystyle 1650$
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CBSE Class 10 Mathematics past-paper question from the 2024 board exam, with the answer as CBSE’s own marking scheme gives it. Where our answers come from.