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Mathematics · 2023 · 2 marks
CBSE 2023 · Region 6 · Set 1 · Q23
Find the length of the shadow on the ground of a pole of height 18 m when angle of elevation θ of the sun is such that tan θ=6/7.
Find the length of the shadow on the ground of a pole of height $\displaystyle 18$ m when angle of elevation $\displaystyle \theta$ of the sun is such that $\displaystyle \tan \theta=\frac{6}{7}$.
Marking-scheme solution
Pole of height $\displaystyle \mathrm{AB}=18 \mathrm{~m}$
AP = length of shadow
In $\displaystyle \triangle \mathrm{APB}, \tan \theta=\frac{18}{A P}$
\[\begin{aligned}
\frac{6}{7} & =\frac{18}{A P} \\
\Rightarrow \mathrm{AP} & =21 \mathrm{~m}
\end{aligned}
\]
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