Find the greatest number less than 10,000 which is exactly divisible by 48, 60 and 65.

\[48=2^{4} \times 3, \quad 60=2^{2} \times 3 \times 5, \quad 65=5 \times 13 \] L.C.M. \(\displaystyle (48,60,65)=2^{4} \times 3 \times 5 \times 13=3120\) ∴ Highest multiple of $\displaystyle 3120$, less than \(\displaystyle 10,000=3120 \times 3=9360\)