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Mathematics · 2022 · 2 marks
CBSE 2022 · Region 3 · Set 3 · Q3
Find the common difference 'd' of an AP whose first term is $\displaystyle 10$ and the sum of the first $\displaystyle 14$ terms is 1505.
Marking-scheme solution
Here \(\displaystyle a=10, n=14, \mathrm{~S}_{14}=1505\)
\(\displaystyle 1505=\frac{14}{2}[20+13 d]\)
\(\displaystyle \Rightarrow d=15\)
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CBSE Class 10 Mathematics past-paper question from the 2022board exam, with the answer as CBSE’s own marking scheme gives it. Where our answers come from.