Find the area of the sector of a circle of radius 42 cm and of central angle 30^°. Also, find the area of the corresponding major sector. [Use π=22/7…

Area of minor sector \(\displaystyle =\frac{30}{360} \times \frac{22}{7} \times 42 \times 42 =462 \mathrm{~cm}^{2}\) Angle of corresponding major sector \(\displaystyle =330^{\circ}\) Area of Major Sector \(\displaystyle =\frac{330}{360} \times \frac{22}{7} \times 42 \times 42\) \(\displaystyle =5082 \mathrm{~cm}^{2}\)