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Mathematics · 2026 · 5 marks
CBSE 2026 · Region 5 · Set 2 · Q32
By selling an article for ₹ $\displaystyle 48$, a trader loses as much percent as half of the cost price of the article. Calculate the cost price and loss amount of the article.
Marking-scheme solution
Let the cost price (CP)of the article be ₹ \(\displaystyle x\)
Loss \(\displaystyle =\frac{x}{2} \%\) of \(\displaystyle x=\frac{x^{2}}{200}\)
Selling price \(\displaystyle =48=x-\frac{x^{2}}{200}\)
\(\displaystyle \Rightarrow x^{2}-200 x+9600=0\)
\(\displaystyle \Rightarrow(x-120)(x-80)=0\)
\(\displaystyle \Rightarrow x=120,80\)
When \(\displaystyle \mathrm{CP}=₹ 120\), Loss \(\displaystyle =120-48=₹ 72\)
When \(\displaystyle \mathrm{CP}=₹ 80\), Loss \(\displaystyle =80-48=₹ 32\)
CBSE Class 10 Mathematics past-paper question from the 2026board exam, with the answer as CBSE’s own marking scheme gives it. Where our answers come from.