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Mathematics · 2025 · 2 marks
CBSE 2025 · Region 1 · Set 1 · Q25
A person is standing at P outside a circular ground at a distance of 26 m from the centre of the ground. He found that his distances from the points…
A person is standing at P outside a circular ground at a distance of $\displaystyle 26$ m from the centre of the ground. He found that his distances from the points A and B on the ground are $\displaystyle 10$ m (PA and PB are tangents to the circle). Find the radius of the circular ground.
Marking-scheme solution
\(\displaystyle \angle \mathrm{OAP}=90^{\circ}\)
In right \(\displaystyle \Delta \mathrm{OAP}\),
\[\begin{aligned}
& (26)^{2}=\mathrm{OA}^{2}+(10)^{2} \\
\Rightarrow & \mathrm{OA}=\sqrt{576}=24 \\
\therefore & \text { radius }=24 \mathrm{~m}
\end{aligned}
\]
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CBSE Class 10 Mathematics past-paper question from the 2025 board exam, with the answer as CBSE’s own marking scheme gives it. Where our answers come from.