✓ Board-verified
Mathematics · 2024 · 3 marks
CBSE 2024 · Region 2 · Set 3 · Q30
A dealer sells an article for ₹ $\displaystyle 75$ and gains as much percent as the cost price of the article. Find the cost price of the article.(a)/DA2AB/$\displaystyle 21$
A dealer sells an article for ₹ $\displaystyle 75$ and gains as much percent as the cost price of the article. Find the cost price of the article.
(a)
/DA2AB/$\displaystyle 21$
Marking-scheme solution
Let the cost price of the article be ₹ x
∴ Gain \(\displaystyle \%=\mathrm{x}\)
\[\begin{aligned}
& \Rightarrow \mathrm{x}=\frac{75-\mathrm{x}}{\mathrm{x}} \times 100 \\
& \Rightarrow \mathrm{x}^{2}+100 \mathrm{x}-7500=0 \\
& \Rightarrow(\mathrm{x}-50)(\mathrm{x}+150)=0 \\
& \mathrm{x} \neq-150 \therefore \mathrm{x}=50
\end{aligned}
\]
So, the cost price of the article is ₹ $\displaystyle 50$
CBSE Class 10 Mathematics past-paper question from the 2024board exam, with the answer as CBSE’s own marking scheme gives it. Where our answers come from.