A chord of a circle of radius $\displaystyle 10$ cm subtends a right angle at the centre of the circle. Find the area of the corresponding minor segment. [Use $\displaystyle \pi=3 \cdot 14$ ]

Area of minor segment ACB = Area of sector OACB - Area of right \(\displaystyle \triangle \mathrm{OAB}\) Area of sector OACB \(\displaystyle =\frac{90}{360} \times 3.14 \times 10 \times 10\) \(\displaystyle =78.5 \mathrm{~cm}^{2}\) Area of right \(\displaystyle \Delta \mathrm{OAB}=\frac{1}{2} \times 10 \times 10\) \(\displaystyle =50 \mathrm{~cm}^{2}\) Area of minor segment \(\displaystyle \mathrm{ACB}=(78.5-50)\) \(\displaystyle =28.5 \mathrm{~cm}^{2}\)