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Mathematics · 2026 · 2 marks
CBSE 2026 · Region 5 · Set 1 · Q25
A bag contains 25 balls. Some of them are yellow and others are green. One ball is drawn at random. If probability of getting a green ball is 3/5,…
A bag contains $\displaystyle 25$ balls. Some of them are yellow and others are green. One ball is drawn at random. If probability of getting a green ball is $\displaystyle 3$/$\displaystyle 5$, then find the number of yellow balls.
Marking-scheme solution
\(\displaystyle \mathrm{P}(\) getting a yellow ball \(\displaystyle )=1-\mathrm{P}(\) getting a green ball \(\displaystyle )\)
\(\displaystyle \Rightarrow \frac{\text { Number of yellow balls }}{25}=1-\frac{3}{5}=\frac{2}{5}\)
⇒ Number of yellow balls \(\displaystyle =25 \times \frac{2}{5}=10\)
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CBSE Class 10 Mathematics past-paper question from the 2026 board exam, with the answer as CBSE’s own marking scheme gives it. Where our answers come from.